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lang-bash
-eqoperator cannot compare two strings, as long as both arguments are already strings, oh well.eq, being a string, should be used for string comparisons, while=, being a mathematical symbol, should be used for numerical comparisons, but alas it's not the case.[ 05 -eq 5 ]is true, but[ 05 = 5 ]is not -- they're different strings that represent the same integer. Also,[ 5 -lt 11 ]is true, but[ 5 '<' 11 ]is not, because 5 is less than 11 numerically, but comes after it "alphabetically" (i.e. in sorting order). BTW,=is preferred over==withtestand[ ], for compatibility reasons.