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Updated gawk documentation link

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edit approved Dec 23, 2021 at 16:01

It depends on your awk version (you probably have to use gawk instead of awk) or directly run date in your awk commandline, but

awk 'NR%13==0 { printf  "%d %s\n",  systime(), $0 ; fflush(stdout) }'

will print the current timestamp in front of the current line. For more information have a look at the gawk documentation gawk documentation about time functions.

It depends on your awk version (you probably have to use gawk instead of awk) or directly run date in your awk commandline, but

awk 'NR%13==0 { printf  "%d %s\n",  systime(), $0 ; fflush(stdout) }'

will print the current timestamp in front of the current line. For more information have a look at the gawk documentation about time functions.

It depends on your awk version (you probably have to use gawk instead of awk) or directly run date in your awk commandline, but

awk 'NR%13==0 { printf  "%d %s\n",  systime(), $0 ; fflush(stdout) }'

will print the current timestamp in front of the current line. For more information have a look at the gawk documentation about time functions.

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answered Jun 5, 2012 at 23:47

Ulrich Dangel

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It depends on your awk version (you probably have to use gawk instead of awk) or directly run date in your awk commandline, but

awk 'NR%13==0 { printf  "%d %s\n",  systime(), $0 ; fflush(stdout) }'

will print the current timestamp in front of the current line. For more information have a look at the gawk documentation about time functions.