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Fix off by 1 error

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edited Jun 18, 2017 at 18:41

4.3k
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One way to do that in awk would be like:

###Code:

$ awk '{ for (i=4; i <<= NF; i++) print $1, $2, $3, $i }' file1

###file1:

10000001 ABC $5.00 ABC01 ABC001 ABC1
10000002 BCD $2.34 BCD01 BCD.go BD.c.2 BDDCD7

###Results:

10000001 ABC $5.00 ABC01
10000001 ABC $5.00 ABC001
10000001 ABC $5.00 ABC1
10000002 BCD $2.34 BCD01
10000002 BCD $2.34 BCD.go
10000002 BCD $2.34 BD.c.2
10000002 BCD $2.34 BDDCD7

One way to do that in awk would be like:

###Code:

$ awk '{ for (i=4; i < NF; i++) print $1, $2, $3, $i }' file1

###file1:

10000001 ABC $5.00 ABC01 ABC001 ABC1
10000002 BCD $2.34 BCD01 BCD.go BD.c.2 BDDCD7

###Results:

10000001 ABC $5.00 ABC01
10000001 ABC $5.00 ABC001
10000002 BCD $2.34 BCD01
10000002 BCD $2.34 BCD.go
10000002 BCD $2.34 BD.c.2

One way to do that in awk would be like:

###Code:

$ awk '{ for (i=4; i <= NF; i++) print $1, $2, $3, $i }' file1

###file1:

10000001 ABC $5.00 ABC01 ABC001 ABC1
10000002 BCD $2.34 BCD01 BCD.go BD.c.2 BDDCD7

###Results:

10000001 ABC $5.00 ABC01
10000001 ABC $5.00 ABC001
10000001 ABC $5.00 ABC1
10000002 BCD $2.34 BCD01
10000002 BCD $2.34 BCD.go
10000002 BCD $2.34 BD.c.2
10000002 BCD $2.34 BDDCD7

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answered Jun 18, 2017 at 18:10

Stephen Rauch

4.3k
15
24
33

One way to do that in awk would be like:

###Code:

$ awk '{ for (i=4; i < NF; i++) print $1, $2, $3, $i }' file1

###file1:

10000001 ABC $5.00 ABC01 ABC001 ABC1
10000002 BCD $2.34 BCD01 BCD.go BD.c.2 BDDCD7

###Results:

10000001 ABC $5.00 ABC01
10000001 ABC $5.00 ABC001
10000002 BCD $2.34 BCD01
10000002 BCD $2.34 BCD.go
10000002 BCD $2.34 BD.c.2