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lang-bash
IFS=. readwork? if that spec was applicable, wouldnt that mean the IFS be taking effect (on word splitting) before theIFS=.got assigned?IFS=. read. An expansion means$variablename.readonly usesIFSafter the command line is processed, it acts like any command (though it implicitly sees even an unexportedIFS). If you did something likevars="a b c"; IFS=. read $vars <<< "1.2.3"; echo $b(with the default value ofIFS) you'd get2, since$varswas word-split with the originalIFS, butreadused the one explicitly given to it.