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lang-bash
echo $((1 ^= 1))didn't work.^=assignment operator. The expression(( foo ^= 1 ))is equivalent to(( foo = foo ^ 1 )). Your example of((1 ^= 1))expands to(( 1 = 1 ^ 1 ))which fails because you can't change the value of1. To make your example work, just use the regular XOR operator^instead of assignment, e.g.:echo $(( 1 ^ 1 )).