How to construct url with http_build_query, but display values without variables?

Question

I'm trying to generate an URL from all values of two arrays by using http_build_query:

Array 1:

$server = array($_GET["server"]);

Array 2:

$data = array($_GET["z_koord"],
        $_GET['x_koord'],
        $_GET["y_koord"],);

The code for generating URL I currently have written:

$server = array(''=>$_GET["server"]);
$data = array($_GET["z_koord"],
        $_GET['x_koord'],
        $_GET["y_koord"],);
$url = '.tile.openstreetmap.org';
$saite = http_build_query($server). $url ."/". http_build_query($data,'','/').".png";

Here's the URL made of code above:

=c.tile.openstreetmap.org/0=6/1=90/2=110.png

Here's the structure of url I'm trying to make:

c.tile.openstreetmap.org/6/90/110.png

I have reviewed some other posts about this topic like this one and this, but those posts aren't completely useful for solving my problem.

So I hope someone with greater knowledge could show me a solution or at least a hint how to get closer to solution.

You’re using completely the wrong function to begin with. The purpose of http_build_query is to create a URL query string, and that means name=value pairs, separated by & (or a different separator character of choice.) — misorude
– misorude, Commented Jul 16, 2019 at 9:39
@misorude What could be the replacement for http_build_query in this case? — Guuuson
– Guuuson, Commented Jul 16, 2019 at 9:44

KIKO Software · Accepted Answer · 2019-07-16 09:37:08Z

2

You could use implode():

$server = $_GET["server"];
$data   = [$_GET["z_koord"],
           $_GET['x_koord'],
           $_GET["y_koord"]];
$url    = '.tile.openstreetmap.org';
$saite  = "$server/$url/" . implode('/', $data) . ".png";

I'm not sure about some things in this code, but the implode() should do the job.

answered Jul 16, 2019 at 9:37

KIKO Software

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1 Comment

Guuuson Over a year ago

implode() worked just fine for me. Thanks for the suggestion!

Guuuson · Accepted Answer · 2019-07-16 10:23:12Z

You are using http_build_query in the wrong way. You just don't need that. There are 2 options, you may use any one of them.

Use implode(), the simplest way to do the job.

$server = array(
    '' => $_GET['server']
);
$data = array(
    $_GET['z_koord'],
    $_GET['x_koord'],
    $_GET['y_koord'],
);
$url   = $server . '.tile.openstreetmap.org';
$saite = $url . '/' . implode("/", $data) . '.png';

Directly create the URL using the Parameters as shown here:

$url   = '.tile.openstreetmap.org' .;
$saite = $_GET['server'] . $url . '/' . $_GET['z_koord'] .'/'. $_GET['x_koord'] . '/'.$_GET['y_koord'] . '.png';

Didn't know about such ways. Thanks for the mentioned options!

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