Shell script variable value not getting update [duplicate]

Question

I'm trying to execute below bash shell script, but not getting the expected output. Possible i'm doing something wrong or it's not the way of doing this.

 #bin/bash
#set -x

path1_one=/home/dell/scripts
echo $path1_one
param_val=path1_one
param1=$( echo "$param_val" | awk -F '_' '{ print $0 }' )

#path2="$path1"
echo $param1

#echo $path2

Output:

/home/dell/scripts

path1_one

Expected Output:

/home/dell/scripts

Both variable value should be same,but don't know why param1 value is not reflecting with path1_one

It isn't obvious why you think your "expected" output is more correct than your actual output. param_val=path1_one assigns the string path1_one to param_val; why would anything "reflect"? — Charles Duffy
– Charles Duffy, Commented Mar 24, 2017 at 16:02
...if you want indirect assignment or indirect expansion, we already have questions unambiguously asking how to do those things and with clear and readable answers. — Charles Duffy
– Charles Duffy, Commented Mar 24, 2017 at 16:04
@CharlesDuffy, param1=path1_one, so it should print the path1_one value which is /home/dell/scripts — subodh
– subodh, Commented Mar 24, 2017 at 16:11
use param_val="$path1_one" instead of param_val=path1_one. as everybody told you. they just used different variables to demonstrate that and expected you to adapt it to your script. — Samuel Kirschner
– Samuel Kirschner, Commented Mar 24, 2017 at 16:20

chepner · Accepted Answer · 2017-03-24 11:12:32Z

3

You need to tell the script that you want to use the value of the variable path1, not the name path1.

Use:

path2="$path1"

edited Mar 24, 2017 at 11:12

chepner

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answered Mar 24, 2017 at 10:52

NullDev

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4 Comments

subodh Over a year ago

NullDev,Thanks for your quick response, please see my updated complete script. please suggest me, how to get the value from path1.

NullDev Over a year ago

still the same... param_val="$path1" but where is path1_one defined?

subodh Over a year ago

i'm expecting param1 to be path1_one value

Charles Duffy Over a year ago

Why do you expect that?

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