Hashtable functionality using objects in JavaScript

Question

Okay, I have the following scenario: I get an object, which is an array with lists. There is always 3 items in the array.

The items inside the lists, has a specific field I am interested in (ISBN13).

I want to build a table like this using JavaScript:

<table>
    <tr>
        <td>Array_1_Item_1_ISBN13</td>
        <td>Array_2_Item_1_ISBN13</td>
        <td>Array_3_Item_1_ISBN13</td>
    </tr>
    <tr>
        <td>Array_1_Item_2_ISBN13</td>
        <td>Array_2_Item_2_ISBN13</td>
        <td>Array_3_Item_2_ISBN13</td>
    </tr>
</table>

In C#, I would just build a dictionary, and:

If I've seen the key before, add a new key
If I have seen the key before, continue building the string

But now I am in jQuery/JS land, and meh.

Below, I have tried to create an object, I use to fill data in. This code have the following issues:

Instead of adding an entry to the object at key isbn13, it adds object.isbn = ...

Not sure if the if() statement works

function setBookTableFromProducts(data) {
var outputArray = {};

// list is an array of books, e-books and audiobooks)
$.each($.parseJSON(data), function (index, value) {
    // single type of book
    $.each(value, function (index_inner, book) {
        var isbn13 = book.ISBN13;
        if (outputArray.isbn13 == null) {
            var newRowStr = '<tr>';
            newRowStr += '<td>' + book.ISBN13 + '</td>';
            outputArray.isbn13 = newRowStr;
        } else {
            outputArray.isbn13 += '<td>' +book.ISBN13+ '</td>';
        }

    });
});

$.each(outputArray, function (index, trArr) {
    trArr += '</tr>';
    $('#bookTable').append(trArr);
});

}

How would you solve this issue? What is wrong with my code? (Oh, and performance doesn't matter)

Don't use newRowStr = '<tr>' and so on. There is a createElement() method for creating nodes and appendChild() for appending them to DOM — Boris Zagoruiko
– Boris Zagoruiko, Commented Nov 5, 2013 at 14:13

lebolo · Accepted Answer · 2013-11-05 14:23:02Z

2

It would help if you provided an example of the input (i.e. $.parseJSON(data)) or maybe created a jsFiddle.

But one possible issue is outputArray.isbn13. You have var isbn13 = book.ISBN13 take some ISBN value (say 9783161484100) then expect to use it as a key to the outputArray object with outputArray.isbn13. However, the key is isbn13 and not outputArray.9783161484100. Instead, try

var isbn13 = book.ISBN13;
if (outputArray[isbn13] == null) {
  ...
}

This will then get interpreted as outputArray.9783161484100.

answered Nov 5, 2013 at 14:23

lebolo

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