I'm trying to xor 2 binaries using python like this but my output is not in binary any help?
a = "11011111101100110110011001011101000"
b = "11001011101100111000011100001100001"
y = int(a) ^ int(b)
print y
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Print in binary format, it should workkarthikr– karthikr2013-10-16 21:21:26 +00:00Commented Oct 16, 2013 at 21:21
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4 Answers
a="11011111101100110110011001011101000"
b="11001011101100111000011100001100001"
y=int(a,2) ^ int(b,2)
print('{0:b}'.format(y))
4 Comments
Robᵩ
If you want the answer to print with the same length, try:
print '{0:0{1}b}'.format(y,len(a))
VP.
please think about update it with a python 3 version compatible, since python 2.x is mostly not supported anymore.
To get the Xor'd binary to the same length, as per the OP's request, do the following:
a = "11011111101100110110011001011101000"
b = "11001011101100111000011100001100001"
y = int(a, 2)^int(b,2)
print bin(y)[2:].zfill(len(a))
[output: 00010100000000001110000101010001001]
Convert the binary strings to an integer base 2, then XOR, then bin() and then skip the first two characters, 0b, hence the bin(y0)[2:].
After that, just zfill to the length - len(a), for this case.
Cheers
Comments
Since you are trying to carryout XOR on the same length binaries, the following should work just fine:
c=[str(int(a[i])^int(b[i])) for i in range(len(a))]
c=''.join(c)
You can avoid the formatting altogether.
Comments
Since you are starting with strings and want a string result, you may find this interesting but it only works if they are the same length.
y = ''.join('0' if i == j else '1' for i, j in zip(a,b))
If they might be different lengths you can do:
y = ''.join('0' if i == j else '1' for i, j in zip(a[::-1],b[::-1])[::-1])
y = a[len(y):] + b[len(y):] + y
