Timeline for Check if an array contains another array with the same consecutive ordering of elements

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Oct 16, 2022 at 9:59	comment	added	hellopeach		your solution fails when it's testing something like `test([1, 2, 3, [10, 1000]], [3, [10, 1000]])` where the `JSON.stringify` hack works fine.
Oct 15, 2022 at 15:38	history	edited	danh	CC BY-SA 4.0	added 828 characters in body
Oct 15, 2022 at 15:20	comment	added	danh		I see it now. I read "contains with the same ordering", literally, and I missed that the OP expects false. I'll make an edit to offer an alternative. (an alternative in case the OP mis-stated their expectation).
Oct 15, 2022 at 15:10	comment	added	Sebastian Simon		The same as mentioned in the question: `false`.
Oct 15, 2022 at 15:06	comment	added	danh		@SebastianSimon, What result do you expect for test(target, [2, 4]) ?
Oct 15, 2022 at 14:59	comment	added	Sebastian Simon		I just noticed, this fails the `test(target, [2, 4])` test. `index` is just the first occurrence within the big array of the next element within the small array, which doesn’t guarantee that all elements must be consecutive.
Oct 15, 2022 at 14:53	comment	added	danh		Smart catch, @SebastianSimon. The entry condition was too lax. Only [] is a subset of []. Edited
Oct 15, 2022 at 14:52	history	edited	danh	CC BY-SA 4.0	added 85 characters in body
Oct 15, 2022 at 14:35	history	answered	danh	CC BY-SA 4.0