Revisions to How do I convert an integer to binary in JavaScript?

Mod Removes Wiki by Makyen♦

occurred Mar 10, 2023 at 0:02

Post Made Community Wiki by Makyen♦

occurred Mar 9, 2023 at 23:59

added 62 characters in body

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edited Aug 10, 2020 at 12:38

barlop

This is how I manage to handle it:

const decbin = nbr => {
  if(nbr < 0){
     nbr = 0xFFFFFFFF + nbr + 1
  }
  return parseInt(nbr, 10).toString(2)
};

This is how I manage to handle it:

const decbin = nbr => {
  if(nbr < 0){
     nbr = 0xFFFFFFFF + nbr + 1
  }
  return parseInt(nbr, 10).toString(2)
};

This is how I manage to handle it:

const decbin = nbr => {
  if(nbr < 0){
     nbr = 0xFFFFFFFF + nbr + 1
  }
  return parseInt(nbr, 10).toString(2)
};

deleted 3 characters in body

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edited Aug 10, 2020 at 7:16

gildniy

This is how I manage to handle it:

const decbin = nbr => {
 number if(nbr < 0){
 &&    nbr = 0xFFFFFFFF + nbr + 1
  }
  return parseInt(nbr, 10).toString(2)
};

This is how I manage to handle it:

const decbin = nbr => {
 number < 0 && nbr = 0xFFFFFFFF + nbr + 1
 return parseInt(nbr, 10).toString(2)
};

This is how I manage to handle it:

const decbin = nbr => {
  if(nbr < 0){
     nbr = 0xFFFFFFFF + nbr + 1
  }
  return parseInt(nbr, 10).toString(2)
};

Source Link

answered Aug 9, 2020 at 19:25

gildniy

This is how I manage to handle it:

const decbin = nbr => {
 number < 0 && nbr = 0xFFFFFFFF + nbr + 1
 return parseInt(nbr, 10).toString(2)
};

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