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Doesn't work. This: await setTimeout(()=>{console.log('first')}, 200); console.log ('second') prints second then first

gregn3
– gregn3

2019-08-30 20:52:44 +00:00
Commented Aug 30, 2019 at 20:52
2

@gregn3 that is the point yes. This is a non blocking solution where code outside the function can continue to execute while a "blocking operation" is completed outside the main program flow. Although the syntax you and Rommy and Mohamad have provided isn't strictly correct due to the requirement for an await to be rapped in an async function (might be a fairly recent addition), also I'm using node.js. This is my tweaked solution. var test = async () => { await setTimeout(()=>{console.log('first')}, 1000); console.log ('second') } I've extended the timeout to show it's usefulness.

azariah
– azariah

2019-11-09 05:57:09 +00:00
Commented Nov 9, 2019 at 5:57

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