Day 1)

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.

Note: If the number is a multiple of both 3 and 5, only count it once.

Solution:

public class Solution {

public int solution(int number) {
    int sum = 0;

    for (int i = 1; i < number; i++) {
        if (i % 3 == 0 || i % 5 == 0) {
            sum += i;
        }
    }

    return sum;
}

}