How to Declare a Method with Variable Arguments in Java

Question

How can I declare a method in Java that accepts a variable number of parameters?

public void exampleMethod(String... strings) {
    // Method body
}

Answer

In Java, you can declare a method that accepts a variable number of arguments using the 'varargs' feature. This allows a method to process an arbitrary number of parameters, enhancing flexibility and ease of use.

public void sumNumbers(int... numbers) {
    int sum = 0;
    for (int num : numbers) {
        sum += num;
    }
    System.out.println("Sum: " + sum);
}

Causes

  • To handle varying numbers of input arguments in a method call efficiently.
  • To avoid overloading methods for different parameter counts, thus keeping the code cleaner.

Solutions

  • Use the '...' syntax after the type in the method declaration.
  • The declared varargs parameter must be the last parameter in the method signature.

Common Mistakes

Mistake: Forgetting to place the varargs parameter as the last parameter in the method declaration.

Solution: Always declare the varargs type as the last parameter to avoid compilation errors.

Mistake: Using multiple varargs parameters in a single method.

Solution: A method can only have one varargs parameter, declared only once.

Helpers

  • Java variable arguments
  • Java varargs
  • Java methods
  • Java programming
  • Dynamic method parameters

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