Question
How can I easily load a classpath resource into a byte array in Java?
byte[] data = ResourceUtils.getResourceAsBytes("/assets/myAsset.bin");
Answer
Loading classpath resources as byte arrays is a common requirement in Java applications. While you can manually read an InputStream into a byte array, there are convenient methods provided by popular libraries that streamline this process.
import org.springframework.core.io.Resource;
import org.springframework.core.io.ResourceLoader;
import java.io.IOException;
import java.nio.file.Files;
public byte[] loadResourceAsBytes(String resourcePath) throws IOException {
Resource resource = resourceLoader.getResource(resourcePath);
return Files.readAllBytes(resource.getFile().toPath());
}
Causes
- Need to read binary files from the classpath.
- Inadequate handling of InputStream to byte array conversion.
- Desire for simpler, more maintainable code.
Solutions
- Use Spring's ResourceUtils to load resources as byte arrays.
- Utilize Apache Commons IO's IOUtils to convert InputStream to byte arrays.
Common Mistakes
Mistake: Forgetting to close the InputStream after reading.
Solution: Always use a try-with-resources statement or ensure the InputStream is closed in a finally block.
Mistake: Not handling IOException while reading the resource.
Solution: Implement appropriate exception handling to manage IOExceptions.
Helpers
- classpath resource
- byte array Java
- ResourceUtils
- Apache Commons IO
- load resource as bytes
- InputStream to byte array