Question
How can I use File.listFiles with FileNameExtensionFilter without encountering a compilation error?
FileNameExtensionFilter filter = new FileNameExtensionFilter("text only","txt");
String dir = "/users/blah/dirname";
File f[] = (new File(dir)).listFiles(filter);
Answer
Using the `File.listFiles(FileFilter filter)` method in Java allows you to filter files based on certain criteria. However, when using `FileNameExtensionFilter`, an important detail about the class hierarchy must be understood to avoid compilation errors.
File[] files = (new File(dir)).listFiles(new FileFilter() {
public boolean accept(File file) {
return file.isFile() && file.getName().endsWith(".txt");
}
});
Causes
- You are trying to use `FileNameExtensionFilter` directly with the `listFiles()` method, but this class does not match the expected parameter type.
Solutions
- Use the correct filter type. Instead of using `FileNameExtensionFilter`, use a custom filter subclassed from `FileFilter`.
- Alternatively, use lambda expressions along with the `Files` class to accomplish similar results.
Common Mistakes
Mistake: Using FileNameExtensionFilter directly with listFiles, which expects a FileFilter.
Solution: Define a custom FileFilter that implements the accept method to check file extensions.
Mistake: Assuming that all filters that extend from FileFilter can be passed interchangeably without checking method signatures.
Solution: Always verify that the method parameter styles match precisely with methods being called.
Helpers
- Java File.listFiles
- FileNameExtensionFilter
- Java FileFilter examples
- Java file extensions
- Java list files in directory