Question
What is the effect of reordering on Java compiler behavior?
int a = 0; int b = 0;
Thread t1 = new Thread(() -> {
a = 1;
b = 2;
});
Thread t2 = new Thread(() -> {
System.out.println(b);
System.out.println(a);
});
Answer
Reordering is an optimization technique used by the Java compiler and the Java Virtual Machine (JVM) to improve performance. However, this can lead to unexpected behavior in multi-threaded applications due to potential visibility and ordering issues.
synchronized(lock) {
a = 1;
b = 2;
} // Ensures that variables are written atomically and visible to other threads.
Causes
- Java's Memory Model allows compilers and processors to perform optimizations that may change the execution order of operations, especially in multithreaded contexts.
- Compiler optimizations assume that variables will not be accessed simultaneously across threads, which can lead to variances in variable state and results.
Solutions
- Use synchronized blocks to ensure that modifications to shared variables are visible to all threads.
- Utilize the `volatile` keyword to inform the JVM that a variable may be modified by different threads, ensuring visibility across threads.
- Implement the `java.util.concurrent` package which provides higher-level concurrency utilities.
Common Mistakes
Mistake: Assuming that the order of statements in a single thread is guaranteed to be preserved during execution.
Solution: Understand that compiler optimizations may reorder instructions within a thread, and use synchronization mechanisms to preserve order.
Mistake: Not marking shared variables as `volatile`, leading to stale data being read by other threads.
Solution: Use the `volatile` keyword for variables shared between threads to ensure visibility.
Helpers
- Java compiler reordering
- Java memory model
- Multithreading in Java
- Thread safety in Java
- Compiler optimizations in Java