Question
Which method from java.lang.Class generates the appropriate input format for Class.forName()?
// Example of using Class.forName()
try {
Class<?> clazz = Class.forName("com.example.MyClass");
} catch (ClassNotFoundException e) {
// Handle exception if class not found
}
Answer
The method you need is the `getName()` method found in the `java.lang.Class` class. This method returns the fully qualified name of the class, which is necessary to properly use `Class.forName()`.
String className = MyClass.class.getName(); // Obtain the fully qualified name
try {
Class<?> clazz = Class.forName(className); // Use the name with Class.forName()
} catch (ClassNotFoundException e) {
e.printStackTrace();
// Handle the exception
}
Causes
- Using an incorrect class name or package name in the argument for Class.forName() can lead to ClassNotFoundException.
- Failing to use the fully qualified name of a class that exists in a different package.
Solutions
- Use ClassName.class.getName() to obtain the fully qualified class name as a String that can be used in Class.forName().
- Ensure that the class you are trying to load is properly included in the classpath.
Common Mistakes
Mistake: Not using the fully qualified class name.
Solution: Always provide the full package name along with the class name.
Mistake: Assuming that a class is always in the default package.
Solution: Check the package declaration and use it in your Class.forName() call.
Helpers
- java.lang.Class
- Class.forName()
- Java dynamic class loading
- getName() method
- Java ClassNotFoundException