Understanding ConcurrentModificationException: Why One Loop Throws It While Another Does Not

Question

What causes ConcurrentModificationException to be thrown in one loop and not in another when iterating over a collection?

List<String> list = new ArrayList<>(Arrays.asList("A", "B", "C"));

for (String s : list) {
    if (s.equals("B")) {
        list.remove(s); // This will throw ConcurrentModificationException
    }
}
for (String s : new ArrayList<>(list)) {
    if (s.equals("B")) {
        // Safe to remove from this copy
        list.remove(s);
    }
}

Answer

ConcurrentModificationException in Java occurs when a collection is modified while iterating over it. Understanding the rules of collection modifications can help prevent this exception.

List<String> list = new ArrayList<>(Arrays.asList("A", "B", "C"));
Iterator<String> iterator = list.iterator(); 
while (iterator.hasNext()) {
    String s = iterator.next();
    if (s.equals("B")) {
        iterator.remove(); // Safe removal
    }
}

Causes

  • Modifying a collection (like adding or removing elements) while iterating through it with a standard iterator, which is not designed for concurrent modification.
  • Using the `foreach` loop on a collection which does not allow modification while iterating.

Solutions

  • Use an explicit iterator to remove elements safely during iteration with `iterator.remove()` method instead.
  • Create a copy of the collection before iterating (as shown in the second loop) to avoid modifying the original collection.

Common Mistakes

Mistake: Modifying the collection directly inside a for-each loop.

Solution: Always prefer using an `Iterator` for safe removal during iteration.

Mistake: Assuming that a copy of the collection can be made implicitly during iteration.

Solution: Explicitly clone or create a new instance of the collection before iterating.

Helpers

  • ConcurrentModificationException
  • Java collection modification
  • iterator remove method
  • safe removal in Java
  • Java foreach loop modification

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