How to Determine If an IP Address Belongs to a Specific Network or Netmask in Java

Question

How can I check if a given IP address is part of a specific network or netmask using Java?

import java.net.InetAddress;
import java.net.UnknownHostException;

public class IPNetworkCheck {
    public static boolean isIPInNetwork(String ip, String network, String netmask) throws UnknownHostException {
        InetAddress ipAddress = InetAddress.getByName(ip);
        InetAddress networkAddress = InetAddress.getByName(network);
        InetAddress netmaskAddress = InetAddress.getByName(netmask);

        byte[] ipBytes = ipAddress.getAddress();
        byte[] networkBytes = networkAddress.getAddress();
        byte[] netmaskBytes = netmaskAddress.getAddress();

        for (int i = 0; i < ipBytes.length; i++) {
            if ((ipBytes[i] & netmaskBytes[i]) != (networkBytes[i] & netmaskBytes[i])) {
                return false;
            }
        }
        return true;
    }
}

Answer

This guide will demonstrate how to determine whether a given IP address falls within a specific network or subnet defined by a netmask in Java. Knowing how to perform this check is valuable for network programming, security, and filtering traffic.

import java.net.InetAddress;
import java.net.UnknownHostException;

public class IPNetworkCheck {
    public static boolean isIPInNetwork(String ip, String network, String netmask) throws UnknownHostException {
        InetAddress ipAddress = InetAddress.getByName(ip);
        InetAddress networkAddress = InetAddress.getByName(network);
        InetAddress netmaskAddress = InetAddress.getByName(netmask);

        byte[] ipBytes = ipAddress.getAddress();
        byte[] networkBytes = networkAddress.getAddress();
        byte[] netmaskBytes = netmaskAddress.getAddress();

        for (int i = 0; i < ipBytes.length; i++) {
            if ((ipBytes[i] & netmaskBytes[i]) != (networkBytes[i] & netmaskBytes[i])) {
                return false;
            }
        }
        return true;
    }
}

Causes

  • Incorrectly formatted IP addresses
  • Netmask inaccuracies
  • Not accounting for different IP classes

Solutions

  • Use the InetAddress class for reliable IP address handling
  • Verify that the IP addresses and netmask are correctly formatted
  • Consider using third-party libraries like Apache Commons IP for advanced scenarios

Common Mistakes

Mistake: Using incorrect IP address formats (e.g., missing segments)

Solution: Ensure IP addresses are in valid formats (e.g., 192.168.1.1, 255.255.255.0).

Mistake: Neglecting to validate if input is an IP or netmask

Solution: Add input validation to confirm that the strings represent valid IP addresses or netmasks.

Helpers

  • Java check IP address network
  • netmask check Java
  • Java IP networking
  • IP address validation Java
  • Java InetAddress example

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