Question
How to check if an integer falls within a specified range in Python?
def is_between(x, lower, upper):
return lower <= x <= upper
Answer
In Python, you can easily check if an integer is between two numbers using comparison operators. This can be useful in various scenarios, such as validating user input, filtering data, or controlling the flow of a program based on numerical conditions.
def is_between(x, lower, upper):
return lower <= x <= upper
# Example Usage
number = 10
print(is_between(number, 5, 15)) # Output: True
print(is_between(number, 10, 10)) # Output: True
print(is_between(number, 11, 15)) # Output: False
Causes
- Checking if a value is within a specific range is a common requirement in programming.
- Using incorrect logical conditions can lead to unexpected results.
Solutions
- Use the syntax `lower <= x <= upper` for clarity and efficiency.
- Consider edge cases, such as when `x` equals `lower` or `upper`.
- Return a boolean result based on the evaluation of the condition.
Common Mistakes
Mistake: Using single equality operator (`=`) instead of comparison operators.
Solution: Always use comparison operators like `<=` or `>=` when checking numerical ranges.
Mistake: Not accounting for edge cases where the number equals the boundaries.
Solution: Ensure your checks include the boundaries by using `<=` and `>=` appropriately.
Helpers
- Python check integer range
- is between function Python
- verify number within range Python
- Python check if number is in range