Question
How can you check that a WebElement is not present in Selenium WebDriver with Java?
WebDriver driver = new ChromeDriver();
driver.get("http://example.com");
try {
WebElement element = driver.findElement(By.id("nonExistingElementId"));
// If we reach this line, the element is present, which is not expected.
Assert.fail("Element should not be present but was found.");
} catch (NoSuchElementException e) {
// Expected exception, element is not found.
} finally {
driver.quit();
}
Answer
In Selenium WebDriver, it is often necessary to verify that certain elements do not exist on a page. This is crucial for ensuring that tests accurately reflect the UI state, especially when validating conditional UI components. Below, we will detail how to assert that a WebElement is not present using Java with Selenium WebDriver, including practical code snippets and essential tips.
try {
WebElement element = driver.findElement(By.id("nonExistingElementId"));
Assert.fail("Element found unexpectedly: " + element.getText());
} catch (NoSuchElementException e) {
System.out.println("Element is not present as expected.");
}
Causes
- Web elements are dynamically loaded and can be absent based on previous user actions.
- The test might attempt to interact with elements that depend on certain application states.
Solutions
- Use a try-catch block to handle NoSuchElementException when searching for the WebElement.
- Utilize Boolean checks with findElements method to ascertain presence without relying on exceptions.
Common Mistakes
Mistake: Failing to properly catch NoSuchElementException can cause the test to break.
Solution: Make sure to use a try-catch block around the findElement() method to manage exceptions.
Mistake: Assuming findElement will always return valid elements without exception handling.
Solution: Always anticipate the potential absence of the element and handle it gracefully.
Helpers
- Selenium WebDriver
- assert element not present
- Java Selenium tutorial
- NoSuchElementException
- testing UI elements