DOI:10.1080/00029890.2018.1449505 - Corpus ID: 125508192
Rupert Property of Archimedean Solids
@article{Chai2018RupertPO, title={Rupert Property of Archimedean Solids}, author={Ying Chai and Liping Yuan and Tudor Zamfirescu}, journal={The American Mathematical Monthly}, year={2018}, volume={125}, pages={497 - 504}, url={https://api.semanticscholar.org/CorpusID:125508192} }
- Ying Chai, Liping Yuan, T. Zamfirescu
- Published in The American mathematical… 24 May 2018
- Mathematics
It is shown that among the 13 Archimedean solids, 8 have this property, namely, the cuboctahedron, the truncated octahedrons, thetruncated cube, the rhombicuboctahedral, the icosidodecahedral, and the truncation dodecahedron.
11 Citations
11 Citations
Optimizing for the Rupert Property
- A. Fredriksson
- Mathematics
- 2024
Abstract A polyhedron is Rupert if it is possible to cut a hole in it and thread an identical polyhedron through the hole. It is known that all 5 Platonic solids, 10 of the 13 Archimedean solids, 9…
The Truncated Tetrahedron Is Rupert
- Gérard Lavau
- Mathematics
- 2019
Abstract A polyhedron has the Rupert property if a straight tunnel can be made in it, large enough so that a copy of can pass through this tunnel. Eight Archimedean polyhedra are known to have the…
A convex polyhedron without Rupert's property
- Jakob SteiningerS. Yurkevich
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A three-dimensional convex body is said to have Rupert's property if its copy can be passed through a straight hole inside that body. In this work we construct a polyhedron which is provably not…
Two Sufficient Conditions for a Polyhedron to be (Locally) Rupert
- Evan Scott
- Mathematics
- 2022
Given two cubes of equal size, it is possible - against all odds - to bore a hole through one which is large enough to pass the other straight through. This preposterous property of the cube was…
Covering of objects related to rupert property
- Pongbunthit Tonpho
- Mathematics
- 2019
One problem related to covering problem is whether one object has Rupert property. An object K in R? has the Rupert property if a hole could be cut through one copy of K with the same size to permit…
The n-Cube is Rupert
- G. HuberK. P. ShultzJ. Wetzel
- Mathematics
- 2018
It is shown that the n-cube is Rupert for each n ⩾ 3, because a straight tunnel can be made in it through which a second congruent oval can be passed.
Cubes and Boxes Have Rupert’s Passages in Every Nontrivial Direction
- A. BezdekZhenyue GuanM. HujterA. Joós
- Mathematics
- 2021
It is proved that cubes and, in fact all, rectangular boxes have Rupert's passages in every direction that is not parallel to the faces, not only for the cube, but also for all other rectangular boxes.
An algorithmic approach to Rupert's problem
- Jakob SteiningerS. Yurkevich
- Mathematics, Computer Science
- 2023
It is proved that Rupert's problem is algorithmically decidable for polyhedra with algebraic coordinates and a probabilistic algorithm is designed which can efficiently prove that a given polyhedron is Rupert.
Extended abstract for
- Jakob SteiningerS. Yurkevich
- Mathematics, Computer Science
- 2022
Undoubtedly the following fact is surprising when being first encountered with: It is possible to cut a hole in the unit cube such that another unit cube can pass through it.
Learning stereometry in a secondary school within GeoGebra’s Augmented Reality app
- M. ShabanovaO. BezumovaE. ZatsepinaS. MalyshevaS. KotovaR. Ovchinnikova
- Computer Science, EducationJournal of Physics: Conference Series
- 2020
A series of tasks for modeling of real objects using GeoGebra AR is presented, assigned to different levels of secondary geometric education: basic, specialized, and advanced.
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8 References
Platonic Passages
- R. JerrardJ. WetzelLiping Yuan
- Mathematics
- 2017
Summary It is well known that a hole can be cut in a cube large enough to permit a second cube of equal size to pass through, a result attributed to Prince Rupert of the Rhine by J. Wallis more than…
Acute Triangulations of the Cuboctahedral Surface
- Xiao FengLiping Yuan
- MathematicsCGGA
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It is proved that the surface of the cuboctahedron can be triangulated into 8 non-obtuse triangles and 12 acute triangles and both bounds are the best possible.
Acute Triangulations of Archimedean Surfaces . The Truncated Tetrahedron
- Xiao FengLiping YuanT. Zamfirescu
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In this paper we prove that the surface of the regular truncated tetrahedron can be triangulated into 10 non-obtuse geodesic triangles, and also into 12 acute geodesic triangles. Furthermore, we show…
Dense packings of the Platonic and Archimedean solids
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Dense particle packings have served as useful models of the structures of liquid, glassy and crystalline states of matter, granular media, heterogeneous materials and biological systems. Probing the…
Universal Stoppers Are Rupert
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John Wetzel [email protected]) earned his Ph.D. at Stanford in 1964 after undergraduate work at Purdue. His entire academic career was spent at the University of Illinois, from which he retired in…
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