sed -n '1h;2,10H;11G;11,$p'
First line, copy h because of new line, then append H until 10.
At line 11, get the hold space
From 11 to end, print.
]# sed -n '1h;2,10H;11G;11,$p' bonj
French: Bonjour
English: Hello
Turkish: Marhaba
Italian: Ciao
German: Hallo
Spanish: Hola
Latin: Salve
Greek: chai-ray
Welsh: Helo
Finnish: Hei
Breton: Demat
This is nicer:
]# seq 20 | sed -n '1h;2,10H;11G;11,$p'
11
1
2
3
4
5
6
7
8
9
10
12
13
14
15
16
17
18
19
20
I take your example:
]# sed -e 1p -e 11p -n bonj
English: Hello
French: Bonjour
...with the -n switch at the end just to show it counts for both expressions.
I have also -n, and then 1h;2,10H, which should be just 1,10H, which is a range of line numbers and a "hold" (store) command. Nothing gets printed, yet.
11,$p is another range. On line 11 it prints what `11G' just got back from hold (ie 1-10) and appended to line 11.
Lines 12 until $ just print themselves, because of -n.
I should make two -e like you:
sed -n -e '1h;2,10H' -e '11G;11,$p'
From 1,10 is hold, from 11,$ is print.
Line 11 has the G first, then the p. It matters, because:
]# seq 20 | sed -n -e '1h;2,10H' -e '11,$p;11G'
11
12
13
14
15
16
17
18
19
20
Here line 12 wipes out what line 11 has gotten after printing.