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echo "anything" | { grep e || true; }

Explanation:

• This will throw an error

  $ echo "anything" | grep e
  $ echo $?
  1
  

• This will not throw an error

  $ echo "anything" | { grep e || true; }
  $ echo $?
  0
  

• DopeGhoti's "no-op" version (Potentially avoids spawning a process, if true is not a builtin), this will not throw an error

  $ echo "anything" | { grep e || :; }
  $ echo $?
  0
  

The || means "or". If the first part of the command "fails" (meaning grep e returns a non-zero exit code) then the part after the || is executed, succeeds and returns zero as the exit code (true always returns zero).