The following script can only print -m but it can't print -n.
#!/bin/sh
echo $@
$ sh test.sh -m
-m
$ sh test.sh -n
$
1 Answer
That's because -n is an actual option to echo. Most tools support -- to mean "there's no more options after this, just arguments", so try if using
echo -- $@
improves the situation.
answered Jul 29, 2022 at 3:42
-
it doesn't, in pretty much any shellilkkachu– ilkkachu2022-07-29 04:09:44 +00:00Commented Jul 29, 2022 at 4:09
$@doesn't print anything, and it deals with-njust fine, though you should be using"$@"instead; or maybe"$*"in this case.