convert one line values to multiple lines with numbering order

Question

The following variable include for example this values

echo $SERVERS


server1,server2,server3,server4,server5

and when I want to pipe them on different lines then I do the following

echo $SERVERS | tr ',' '\n'

server1
server2
server3
server4
server5

now I want to add another pipe ( echo $SERVERS | tr ',' '\n' | ..... ) , in order to print the following expected results

1  ………………  server1
2  ………………… server2
3  ………………… server3
4  ………………… server4
5  ………………… server5
6  ………………  server6
7  ………………… server7
8  ………………… server8
9  ………………… server9
10 ………………… server10
11 ………………… server11
12 ………………… server12

Not sure how to do it but maybe with nc command os similar

Any suggestion?

Answer 1

With awk:

$ servers='server1,server2,server3,server4,server5'

$ awk -v RS=, '{print NR "........" $0}' <<<"$servers"
1........server1
2........server2
3........server3
4........server4
5........server5

or, to output the line numbers with left-padding

awk -v RS=, '{printf "%3d........%s\n",NR,$0}' <<<"$servers"

(choose the field width 3 as appropriate for the size of your server list).

Answer 2

cat -n <<< ${SERVERS//,/$'\n'} 
     1  server1
     2  server2
     3  server3
     4  server4
     5  server5

Answer 3

$ awk -F',' '{for (i=1; i<=NF; i++) printf "%-2d ........ %s\n", i, $i}' <<<"$servers"
1  ........ server1
2  ........ server2
3  ........ server3
4  ........ server4
5  ........ server5