I am trying to read a password from user, i used -s silent flag but read -s is not working from the script but it works if i do it manually from terminal.
error details
project.sh: 3: read: Illegal option -s
you entered
code
maddy@ElementalX:~/Desktop$ cat project.sh
#!/usr/bin/sh
read -s -p "Enter Password: " pswd
echo "you entered $pswd"
maddy@ElementalX:~/Desktop$
The -s option to the built-in utility read is not a standard option, and is unlikely to be implemented in sh. Likewise, the -p option for giving a custom prompt is unlikely to be implemented by a generic sh.
Run your script with bash instead, whose read does support -s for reading from the terminal without echoing the typed-in characters (and also -p). The easiest way to do this is to change the #!-line to point to the bash executable on your system.
In a non-bash shell, you may get a similar effect with
printf 'Enter password: ' >&2
stty -echo
read password
stty echo
sh only ?? because same thing was working if i do it directly from terminal.
sh is not bash, and its read does not implement -s nor -p. Your shell in the terminal is bash, so it supports read -s.