Script hit walltime before completing; creates files from an initial set of input files into output files with different suffix, eg.
file1.ext -> file1.oxt
(note, extensions given are arbitrary).
How do I move only the input files for which there already exist output files into a separate directory before re-running the initial script? Something like 'mv file only if basename(file).oxt exists'. Could do this is other languages, but my knowledge of Bash is extremely lacking here.
Thanks!
There is your bash script:
for file in `ls *.old`
do
BASE="${file%.*}"
if [[ -e ${BASE}.new ]]
then
mv $file /yourdir/
fi
done
Just replace .old and .new with your suffixes and yourdir with your real directory.
ls output is for human consumption - you're not supposed to use it as input data: your code will fail if any of the filenames contains IFS characters; loop over the glob results - that should be bullet-proof as long as you quote your vars
find + bash solution:
find . -type f ! -name "*.oxt" -exec bash -c 'f=$1;
fp="${f%.*}"; [[ -f "$fp.oxt" ]] && mv "$f" dest_dir/' _ {} \;
f=$1 - the full filepath
fp="${f%.*}" - filepath with extension stripped(without extension)
[[ -f "$fp.oxt" ]] - check if the respective "output" file exists
mv "$f" dest_dir/ - move the initial file to dest_dir directory
foo.exthow would I know to look for*.oxtrather than*.axt(or whatever)? Are these mappings stored somewhere?