How can I break out of a while loop, from within a nested case statement? [closed]

Question

In the script below - which prompts the user to confirm that they want to proceed with running a potentially bad script - when the user enters Y at the prompt - it will break out of the case block, only to be sent back into the while loop again.

#! /bin/bash
set -e

echo
echo "bad install start"
echo "-----------------------------------------"

while true; do
        read -p "this script will probably fail - do you want to run anyway?" yn
        case $yn in
                [Yy]*)
                        ##### WHAT GOES HERE?? #####
                        ;;
                [Nn]*)
                        exit ;;
                *)
                        echo "answer y or n" ;;
        esac

        echo "script has broken out of case back into while loop"
done

echo -e "\e[33m Installing bad packagename \e[0m"
apt-get install sdfsdfdfsd

echo "rest of script - will i keep running?"

When n is entered, the script exists entirely as desired. I'd like to know how to make it so that when Y is entered the script breaks out of both the case and the while block, but does not exit entirely. Is there something I can put in for the placeholder ("What goes here??") to do that?

Answer 1

In the case where the user entered "y", you can exit both while and case:

break [n]
       Exit from within a for, while, until, or select loop.  If  n  is
       specified, break n levels.  n must be ≥ 1.  If n is greater than
       the number of enclosing loops, all enclosing loops  are  exited.
       The  return  value is 0 unless n is not greater than or equal to
       1.

In your case, you want to do break 2.

Answer 2

@dhag has a great answer. You can also use:

a=0
while [ "$a" -eq 0 ]; do
     ...
     [Nn]*)
          a=1;
          ;;
      ...
done