How to extract images from video file?

Question

I mean, how to generate images files from a video like screenshots.

Answer 1

Try with ffmpeg

ffmpeg -i inputfile.avi -r 1 -f image2 image-%3d.jpeg

You can read the documentation here

• -i inputfile.avi The video input file is inputfile.avi
• -r 1 extract 1 image per second of video. Replace that number for the number of images you want to get per second.
• -f image2 force image output format, you may probable be able to omit this since the program tries to choose the output images format from the file extension.
• image-%3d.jpeg name of the output images, the %3d indicates that the output generated images will have a sequence number there of 3 decimals, if you want the number padded with zeroes you just need to use %03d.

Answer 2

I have just downloaded the latest version of VLC for Windows 32 - 2.1.2 Rincewind and it works fine to do this.

Steps:

1 - Click Tools > Preferences and click radio button All

2 - Scroll down and click the + sign next to Video to expand

3 - Scroll down and click on Scene Filter and fill in the info for Directory Path prefix (where you want to save frames). Don't click Save.

4 - Scroll up and click on the word Video under Filters

5 - Click the check box for Scene video filter and click Save.

6 - Open and run a video and it will save .png's

7 - To stop saving frames go back to step 5 and uncheck Scene video filter. Easy really once you know where to find the settings.

Answer 3

In VLC you can right click, Video, Take Snapshot

Answer 4

Hope this help

#!/bin/bash
source_dir="."
output_dir="."
input_file_types=(avi wmv flv mkv mpg mp4)
output_file_type="jpg"

convert() {
        echo "" | ffmpeg -ss $ss -y -i "$in_file" -an -f image2 -vframes 1 "$output_dir/$out_file"
}

for input_file_types in "${input_file_types[@]}"
do

        find "$source_dir" -name "*.$input_file_types" -print0 | while IFS= read -r -d $'\0' in_file
        do
                echo "Processing…"
                echo ">Input  "$in_file
                # Replace the file type
                out_file=$(echo $in_file|sed "s/\(.*\.\)$input_file_types/\1$output_file_type/g")
            echo ">Output "$out_file

# get video duration
#    fulltime=`ffmpeg -i "$in_file" 2>&1 | grep 'Duration' | cut -d ' ' -f 4 | sed s/,//`;
#    hour=`echo $fulltime | cut -d ':' -f 1`;
#    minute=`echo $fulltime | cut -d ':' -f 2`;
#    second=`echo $fulltime | cut -d ':' -f 3 | cut -d '.' -f 1`;

#    seconds=`expr 3600 \* $hour + 60 \* $minute + $second`;
#    ss=`expr $seconds / 2`; # from the middle of video



    ss=`expr 10`; # from the 10sec of video



    # Convert the file
                convert "$in_file" "$out_file"

                if [ $? != 0 ]
                then
                    echo "$in_file had problems" >> ffmpeg-errors.log
                fi

                echo ">Finished "$out_file "\n\n"
        done
done

Answer 5

In vlc-3.0.21-15.fc41, use:

1. "Video"
2. "Take Snapshot"

The snapshot shall be saved in file:///$Env:HOME/Pictures: