How to print numbers horizontally? [duplicate]

Question

I would like to print something as 5,4,3,2,1.

This is my program, but it prints the numbers vertically.

numbers=5
i=1
while [ "$i" -le "$numbers" ]
do
echo “$i”
i=$(( $i + 1 ))
done

Do you have any solution that could help me?

Answer 1

There are many ways to do this, here are some:

1. Use seq as @Gnouc suggested.

2. Use brace expansion and convert spaces to commas:

   $ echo {5..1} | sed 's/ /,/g' 
   5,4,3,2,1
   

3. Use your script but change decrement the counter instead of incrementing it and change echo to echo -n (this will work for bash's builtin echo but not for all echo implementations):

   i=5
   while [ "$i" -gt 1 ]
   do
       echo -n "$i,"
       let i--
   done
   echo "$i"    
   

4. Use printf instead:

   i=5
   while [ "$i" -gt 1 ]
   do
       printf "%s," "$i"
       let i--
   done
   printf "%s\n" "$i"    
   

5. Use a variable:

   i=5
   v=5
   while [ "$i" -gt 1 ]
   do
       let i--;
       v=$v,$i
   done
   echo $v
   

Answer 2

With seq, you can do:

$ seq -s, 5 -1 1
5,4,3,2,1

And a perl solution can be portable:

$ perl -e 'print join ",", reverse 1..5'