Find the process which is taking maximum CPU usage if CPU usage is more than 60%?

Question

I am trying to measure the cpu usage of my ubuntu machine and if the cpu usage is more than 60%, then I need to find out the process who has the highest cpu usage and then send out an email saying CPU usage is more than 60% and with the process name which has the highest cpu usage.

When I do top this is what I see.

Cpu0  :  20.0%us,  0.0%sy,  0.0%ni,100.0%id,  0.0%wa,  0.0%hi,  0.0%si,  0.0%st
Cpu1  :  34.0%us,  0.0%sy,  0.0%ni,100.0%id,  0.0%wa,  0.0%hi,  0.0%si,  0.0%st
Cpu2  :  17.0%us,  0.0%sy,  0.0%ni,100.0%id,  0.0%wa,  0.0%hi,  0.0%si,  0.0%st
Cpu3  :  20.0%us,  0.0%sy,  0.0%ni,100.0%id,  0.0%wa,  0.0%hi,  0.0%si,  0.0%st

I came up with the below script which only finds out the cpu load but not the cpu usage. How do I achieve above thing?

#!/bin/bash

top -bn1 | grep load | awk '{printf "CPU Load: %.2f\n", $(NF-2)}' 

To send an email, I use below command and it works for me -

echo "Body" | mailx -r "[email protected]" -s "SUBJECT" "[email protected]"

Answer 1

using awk:

ps aux --sort=-%cpu | awk 'NR==1{print $2,$3,$11}NR>1{if($3!=0.0) print $2,$3,$11}' > some_file.txt

the above code will give all program with non-zero cpu usage.
will give you pid,%cpu, command_name

if you want cpu usage greater than equal to 60 replace $3!=0.0 to $3>=60

I have saved the output in file some_file.txt. you can cat the file and pipe it to mail command.

try like this: to send mail

cat some_file.txt | mailx -r "[email protected]" -s "SUBJECT" "[email protected]"