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  • The reason you don't parse the output of ls (without -l) is that it's newline delimited, while filenames can be made of any number of lines. With '%s\n', you're printing the file names newline delimited just the same. To print list of file paths in a way that can be processed reliably, you want NUL ('%s\0' or GNU ls --zero) instead of NL as the delimiter (and use sort -z, gawk -v RS='\0' etc assuming GNU implementations) Commented Aug 18 at 18:45