You can create a for loop, to iterate through the directories you want stored in a variable
My structure looks like:
:~/test1$ find . | sort
.
./dir1
./dir1/dir1-a
./dir1/dir1-a/file1a-a
./dir1/dir1-a/file1a-b
./dir1/dir1-a/file1a-c
./dir1/dir1-a/file1a-d
./dir1/dir1-b
./dir1/dir1-b/file1b-a
./dir1/dir1-b/file1b-b
./dir1/dir1-b/file1b-c
./dir1/dir1-c
./dir1/dir1-c/file1c-a
./dir1/dir1-c/file1c-b
./dir1/dir1-d
./dir1/dir1-d/file1d-a
./dir1/file1-a
./dir1/file1-b
./dir2
./dir2/dir2-a
./dir2/dir2-b
./dir2/dir2-c
./test.sh
Note dir1 contains files and folders. You haven't said what you want to do with the sub-folders, or if any will exist.
#!/bin/bash
DIR=( "/home/aubs/test1/dir1" "/home/aubs/test1/dir2" )
for Item in $"${DIR[*]DIR[@]"}
do
echo "Scanning $Item"
COUNT_FILES=$(find "$Item" -maxdepth 1 -type f | wc -l)
echo "contains $COUNT_FILES files"
done
Everything you want doing on each if the items in DIR should be put between the do and done, the directory name on each iteration is $Item.
$ ./test.sh
Scanning /home/aubs/test1/dir1
contains 2 files
Scanning /home/aubs/test1/dir2
contains 0 files
Using ${#dir_files[@]} gives 6 and 3 for my test, which is clearly taking directories into account too. My example uses find "$Item" -maxdepth 1 -type f which only counts the number of files in the directory, and does not look into sub-directories. It then pipes it to wc -l which counts how many lines there are.
You also haven't taken into account if you want to take ownership of the files in the folder either.