I have a scenario where I am looping through all directories and subdirectories in a given path if a file with specific extension (.txt) is found storing the name of the directories and subdirectories in array later which I read and execute command on those directories.

Here is what I am performing:

!/bin/bash
x=( $(find . -name "*.txt") ); echo "${x[@]}"
for item in "${x[@]}"; { echo "$item"; }

Currently I am getting the output as

./dir1/file1.txt
./dir1/file2.txt
./dir2/subdir1/subdir2/file3.txt

but what I want to achieve is in the array x there should not be any duplicates even if the dir contains more than one .txt file and also I dont want to store the file name in as a path, array should contain only the directory name.

expected output:

./dir1
./dir2/subdir1/subdir2/

I have a scenario where I am looping through all directories and subdirectories in a given path; if a file with specific extension (.txt) is found, store the name of the directories and subdirectories in an array. Later, I read and execute commands on those directories.

Here is what I am performing:

!/bin/bash
x=( $(find . -name "*.txt") ); echo "${x[@]}"
for item in "${x[@]}"; { echo "$item"; }

My current output is:

./dir1/file1.txt
./dir1/file2.txt
./dir2/subdir1/subdir2/file3.txt

but what I want to achieve is in the array x there should not be any duplicates even if the dir contains more than one .txt file. Additionally, I don't want to store the file name in as a path; the array should contain only the directory name.

The expected output:

./dir1
./dir2/subdir1/subdir2/