I have a line of code I want to use, but I want it to loop through all the columns in a file, I can do it outside of awk but its really slow. My problem is that I'm not good at looping inside awk, I can run a simple awk loop but this needs something that I can't do yet. So if you can explain how you solve this question it will help me in the future.
The awk command at the moment will output the percentage equivalent of each integer within the selected column ($i). This is the current awk command:
awk -F ',' -v x=$i 'FNR==NR{s+=$x;next;} {printf "%s\n",100*$x/s}' File File
Example input for the above command:
1
4
3
2
Example output for the above command:
10.00000
40.00000
30.00000
20.00000
I need to loop in awk for all of the columns in the file (the file column number is unknown)
so if the input had more than one column, the example input could be:
1,4,2
4,4,1
3,1,6
2,1,1
Example output:
10.00000,40.00000,20.00000
40.00000,40.00000,10.00000
30.00000,10.00000,60.00000
20.00000,10.00000,10.00000
This is the attempt I made (below), obviously its wrong, I tried running a loop for both sections but that didn't give me any output at all.
awk -F"," 'NR==FNR { for (i=1;i<=NF;i++) {s+=$i;next;} next } { for (i=1;i<=NF;i++)printf "%s%%\n",100*$i/s }' File File```File
