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noAnton
noAnton
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I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique

Note: This approach will not work if the search-pattern contains a //

I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique

Note: This approach will not work if the search-pattern contains a /

I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique

Note: This approach will not work if the search-pattern contains a /

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noAnton
noAnton
  • 369
  • 1
  • 6

I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique

Note: This approach will not work if the search-pattern contains a /

I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique

I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique

Note: This approach will not work if the search-pattern contains a /

Source Link
noAnton
noAnton
  • 369
  • 1
  • 6

I think with the default capabilities of grep there in no way of doing this.

You could go with something like this, which is just a "small" regex:

grep -r asdf | sed '#^.*/##' | sort --unique