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Just a guess:

You a trying to run a Bash built-in command in a chroot like this:

chroot <PATH> bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>

But your chroot doesn't have any interpreter running, which could understand bind. Does the following work:

chroot <PATH> bash -c "bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>"

PS
As @mosvy said, first as answer and then as comment, you can pass the enviroment with the call of chroot:

INPUTRC=/path/to/inputrc chroot <jail> bash 

Just a guess:

You are trying to run a Bash built-in command in a chroot like this:

chroot <PATH> bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>

But your chroot doesn't have any interpreter running, which could understand bind. Does the following work:

chroot <PATH> bash -c "bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>"

PS
As @mosvy said, first as answer and then as comment, you can pass the environment with the call of chroot:

INPUTRC=/path/to/inputrc chroot <jail> bash 

Just a guess:

You a trying to run a Bash built-in command in a chroot like this:

chroot <PATH> bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>

But your chroot doesn't have any interpreter running, which could understand bind. Does the following work:

chroot <PATH> bash -c "bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>"

PS As mosvy said, first as answer and then as comment, you can pass the enviroment with the call of chroot:

INPUTRC=/path/to/inputrc chroot <jail> bash 

Just a guess:

You a trying to run a Bash built-in command in a chroot like this:

chroot <PATH> bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>

But your chroot doesn't have any interpreter running, which could understand bind. Does the following work:

chroot <PATH> bash -c "bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>"

PS 
As @mosvy said, first as answer and then as comment, you can pass the enviroment with the call of chroot:

INPUTRC=/path/to/inputrc chroot <jail> bash 

Just a guess:

You a trying to run a Bash built-in command in a chroot like this:

chroot <PATH> bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>

But your chroot doesn't have any interpreter running, which could understand bind. Does the following work:

chroot <PATH> bash -c "bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>"

Just a guess:

You a trying to run a Bash built-in command in a chroot like this:

chroot <PATH> bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>

But your chroot doesn't have any interpreter running, which could understand bind. Does the following work:

chroot <PATH> bash -c "bind -f <PATH_IN_CHROOT>/.inputrc && <PROGRAM_TO_RUN>"

PS As mosvy said, first as answer and then as comment, you can pass the enviroment with the call of chroot:

INPUTRC=/path/to/inputrc chroot <jail> bash