Return to Answer

-r needed to account for the case where the first find doesn't find anything. --maxargs redundant with -I. Missing `-d`. Better use `+` than `;` to avoid running one ls per file

Source Link

edited Jan 7, 2020 at 9:21

Stéphane Chazelas

584.7k
96
1.1k
1.7k

Following hint by @muru to use -I in xargs, the working command (assuming GNU implementations of find and xargs) is:

find "path1" -size 0 -printf "%f\0" |
  xargs -0r0 -I mystr --max-args=1 find "path2" -name mystr -exec ls -lld {} \; +

(that assumes the names of the empty files don't contain wildcard characters as -name interprets its argument as a wildcard pattern)

Following hint by @muru to use -I in xargs, the working command is:

find "path1" -size 0 -printf "%f\0" | xargs -0 -I mystr --max-args=1 find "path2" -name mystr -exec ls -l {} \;

Following hint by @muru to use -I in xargs, the working command (assuming GNU implementations of find and xargs) is:

find "path1" -size 0 -printf "%f\0" |
  xargs -r0 -I mystr find "path2" -name mystr -exec ls -ld {} +

(that assumes the names of the empty files don't contain wildcard characters as -name interprets its argument as a wildcard pattern)

Source Link

answered Jan 7, 2020 at 6:50

Marisha

Following hint by @muru to use -I in xargs, the working command is:

find "path1" -size 0 -printf "%f\0" | xargs -0 -I mystr --max-args=1 find "path2" -name mystr -exec ls -l {} \;