Timeline for How to specify AND / OR operators (conditions) for case statement?
Current License: CC BY-SA 4.0
9 events
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| May 11, 2024 at 13:36 | history | edited | Jeff Schaller♦ | CC BY-SA 4.0 |
Missing word
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| Oct 30, 2019 at 17:00 | comment | added | user232326 |
For booleans (0 or 1) A and B, the usual solution is case $A$B in 11) .... . Simpler.
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| Oct 29, 2019 at 16:25 | comment | added | Stéphane Chazelas |
Note that zsh had ;| (also supported by mksh) before (2007) bash added ;;& (2009) for the same thing (;& itself comes from ksh88e, added to zsh in 1997 and bash in 2009).
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| Oct 29, 2019 at 14:54 | history | edited | Jeff Schaller♦ | CC BY-SA 4.0 |
added nocasematch to the bash portion -- thanks to glenn jackman!
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| Oct 28, 2019 at 18:51 | comment | added | smc | Thanks @jeff-schaller for the explanation, also I have corrected my question after George pointed out about the incorrect placement of "words begins/ends with" part. | |
| Oct 28, 2019 at 18:48 | vote | accept | smc | ||
| Oct 28, 2019 at 18:48 | vote | accept | smc | ||
| Oct 28, 2019 at 18:48 | |||||
| Oct 28, 2019 at 18:15 | comment | added | George Vasiliou |
I was preparing a similar answer using ;;& but i was late! +1 for the nice answer :-) You can also fake a kind of and using something like [0-9]*);;&*[0-9]) echo "word begins and ends with number";;
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| Oct 28, 2019 at 18:13 | history | answered | Jeff Schaller♦ | CC BY-SA 4.0 |