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    I was preparing a similar answer using ;;& but i was late! +1 for the nice answer :-) You can also fake a kind of and using something like [0-9]*);;&*[0-9]) echo "word begins and ends with number";; Commented Oct 28, 2019 at 18:15
  • Thanks @jeff-schaller for the explanation, also I have corrected my question after George pointed out about the incorrect placement of "words begins/ends with" part. Commented Oct 28, 2019 at 18:51
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    Note that zsh had ;| (also supported by mksh) before (2007) bash added ;;& (2009) for the same thing (;& itself comes from ksh88e, added to zsh in 1997 and bash in 2009). Commented Oct 29, 2019 at 16:25
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    For booleans (0 or 1) A and B, the usual solution is case $A$B in 11) .... . Simpler. Commented Oct 30, 2019 at 17:00