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  • 1
    Are you looking for: grep -l "Updating" * | xargs sed 's/begin-\([0-9]*\).end/\1/', or grep -l "Updating" * | sed 's/begin-\([0-9]*\).end/\1/'? It looks like you want one of these, but provide example input and output to clarify. Commented Sep 23, 2019 at 16:11
  • 2
    Moving away from your abstract, can you explain using example input and output what it is that you want to do. Commented Sep 23, 2019 at 16:18
  • 5
    You seem to be focused on an XY Problem. Please state the actual goal instead of what you imagine to be the solution Commented Sep 23, 2019 at 16:22
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    I am still trying to understand your example. Commented Sep 23, 2019 at 16:27
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    Getting a list of filenames from grep -l is no better than parsing ls unless you're using GNU grep with the -Z option for NUL-separated output (note freebsd grep's -z doesn't work with -l). Use grep -l -Z ... Commented Sep 24, 2019 at 4:37