Timeline for Using `printf` to print variable containing `%` percent sign results in "bash: printf: `p': invalid format character"
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
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| Mar 25, 2024 at 8:53 | comment | added | Stripy42 | This should be the accepted answer. As it actually has a working fix. The accepted answer talks about passing variables. But it is clear that there is no intention to pass variables, just the string has a % sign. which in my case I have no control over. | |
| May 16, 2019 at 20:40 | review | First posts | |||
| May 16, 2019 at 21:13 | |||||
| May 16, 2019 at 20:39 | history | answered | BMDan | CC BY-SA 4.0 |