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Tried this approach. However, the results I am getting is NaN. Not sure if I am missing something here. perl -MMath::BigFloat -ape 'my $s=0; $s += new Math::BigFloat($_) for @F[4..15]; s/$/ $s/' input

Parix
– Parix

2019-01-24 17:52:21 +00:00
Commented Jan 24, 2019 at 17:52
that means that any of the fields from the 5th to 16th is not a number. Notice that in perl array indexes start from 0, as in C, not from 1 as in awk or Fortran.

user313992
– user313992

2019-01-24 18:05:07 +00:00
Commented Jan 24, 2019 at 18:05
@Parix In your awk script, you have $3+...+$14; that should translate to @F[2..13] in perl, not to @F[4..15].

user313992
– user313992

2019-01-25 02:26:09 +00:00
Commented Jan 25, 2019 at 2:26

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