Timeline for Compare dates using awk in bash
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 19, 2018 at 20:50 | vote | accept | Μάριος Τσοκανάς | ||
| Nov 17, 2018 at 22:41 | answer | added | RudiC | timeline score: 1 | |
| Nov 17, 2018 at 22:33 | comment | added | RudiC | May I doubt that it works with the first date format either? | |
| Nov 17, 2018 at 13:42 | answer | added | user321447 | timeline score: 3 | |
| Nov 17, 2018 at 13:31 | history | edited | Μάριος Τσοκανάς | CC BY-SA 4.0 |
added 14 characters in body
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| Nov 17, 2018 at 13:24 | history | edited | Μάριος Τσοκανάς | CC BY-SA 4.0 |
added 14 characters in body
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| Nov 17, 2018 at 13:20 | comment | added | Jeff Schaller♦ | Please edit that incoming date format into the question, so answerers knows how to compare it. Thank you! | |
| Nov 17, 2018 at 12:55 | comment | added | Μάριος Τσοκανάς | Not exactly, the command i use is like this ./exec.sh -f <file> --born-since <DD/MM/YYYY>. | |
| Nov 17, 2018 at 12:51 | history | edited | Jeff Schaller♦ |
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| Nov 17, 2018 at 12:51 | comment | added | Jeff Schaller♦ | I assume (please confirm) that the first line of code in your question is part of a script which expects a filename as the 2nd parameter and a date (in the format of DD-MM-YYYY?) as the 4th parameter? | |
| Nov 17, 2018 at 10:59 | history | asked | Μάριος Τσοκανάς | CC BY-SA 4.0 |