Revisions to Rename a group of files to a string that exists inside each one

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edited Apr 5, 2019 at 23:30

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Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${fdir}/${newname}"
done

I hope this helps!

UPDATE: Using jq -r as suggested by @steeldriver. Thanks!

Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${fdir}/${newname}"
done

I hope this helps!

UPDATE: Using jq -r as suggested by @steeldriver. Thanks!

Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${fdir}/${newname}"
done

UPDATE: Using jq -r as suggested by @steeldriver. Thanks!

Using `jq -r` as suggested by steeldriver.

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edited Jul 27, 2018 at 1:42

filbranden

22.6k
4
65
87

Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq -r '.billingAccountList[0]' "${fname}" | tr -d \").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq -r '.billingAccountList[0]' "${fname}" | tr -d \").json
    mv "${fname}" "${fdir}/${newname}"
done

I hope this helps!

UPDATE: Using jq -r as suggested by @steeldriver. Thanks!

Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq '.billingAccountList[0]' "${fname}" | tr -d \").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq '.billingAccountList[0]' "${fname}" | tr -d \").json
    mv "${fname}" "${fdir}/${newname}"
done

I hope this helps!

Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq -r '.billingAccountList[0]' "${fname}").json
    mv "${fname}" "${fdir}/${newname}"
done

I hope this helps!

UPDATE: Using jq -r as suggested by @steeldriver. Thanks!

Source Link

answered Jul 27, 2018 at 1:00

filbranden

22.6k
4
65
87

Use a loop to handle the files one by one.

For instance, with while read:

find . -name '*.json' | while read fname; do
    newname=$(jq '.billingAccountList[0]' "${fname}" | tr -d \").json
    mv "${fname}" "${newname}"
done

Using for might be possible, but it's more sensitive to spaces in the names of the files:

for fname in $(find . -name '*.json'); do
    ... (same as above) ...

Also note that you're moving the files into the current directory, as the original path is being stripped, so if you want to keep the directory structure:

find . -name '*.json' | while read fname; do
    fdir=$(dirname "${fname}")
    newname=$(jq '.billingAccountList[0]' "${fname}" | tr -d \").json
    mv "${fname}" "${fdir}/${newname}"
done

I hope this helps!

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