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I have 2 small functions to abbreviate set -x / set +x, namely:

sx () {
    export PS4='+ [${BASH_SOURCE##*/}:${LINENO}]'
    set -x
}

and

sz () {
    set +x
    export PS4=
}

These 2 functions are in a file functons.sh which is sourced from ~/.bashrc, and visible online here.

Immediately after logging in to a new bash session I try to find out where the sz() function is like this:

$ shopt -s extdebug; declare -F sz; shopt -u extdebug
sz 25 /Users/jab/src/git/hub/jab/src/bash/keyboard/z.sh

This shows that bash thinks the sz() function is declared in z.sh, but at that line there is a different function, zzz(), online here.

The result for the sx() function (and all my myriad other functions) is correct

$ shopt -s extdebug; declare -F sx; shopt -u extdebug
sx 428 /Users/jab/src/git/hub/jab3/src/bash/functons.sh

Why does the declare -F comand get the wrong result for the sz function?

I have 2 small functions to abbreviate set -x / set +x, namely:

sx () {
    export PS4='+ [${BASH_SOURCE##*/}:${LINENO}]'
    set -x
}

and

sz () {
    set +x
    export PS4=
}

These 2 functions are in a file functons.sh which is sourced from ~/.bashrc, and visible online here.

Immediately after logging in to a new bash session, I try to find out where the sz() function is like this:

$ shopt -s extdebug; declare -F sz; shopt -u extdebug
sz 25 /Users/jab/src/git/hub/jab/src/bash/keyboard/z.sh

This shows that bash thinks the sz() function is declared in z.sh, but at that line there is a different function, zzz(), online here.

The result for the sx() function (and all my myriad other functions) is correct

$ shopt -s extdebug; declare -F sx; shopt -u extdebug
sx 428 /Users/jab/src/git/hub/jab3/src/bash/functons.sh

Why does the declare -F command get the wrong result for the sz function?

I have 2 small functions to abbreviate set -x / set +x, namely:

sx () {
    export PS4='+ [${BASH_SOURCE##*/}:${LINENO}]'
    set -x
}

and

sz () {
    set +x
    export PS4=
}

These 2 functions are in a file functons.sh which is sourced from ~/.bashrc, and visible online here.

Immediately after logging in to a new bash session I try to find out where the sz() function is like this:

$ shopt -s extdebug; declare -F sz; shopt -u extdebug
sz 25 /Users/jab/src/git/hub/jab/src/bash/keyboard/z.sh

This shows that bash thinks the sz() function is declared in z.sh, but at that line there is a different function, zzz(), online here.

The result for the sx() function (and all my myriad other functions) is correct

$ shopt -s extdebug; declare -F sx; shopt -u extdebug
sx 428 /Users/jab/src/git/hub/jab3/src/bash/functons.sh

Why does the declare -F comand get the wrong result for the sz function? Do I need extra options (to the command itself or shopt)?

I have 2 small functions to abbreviate set -x / set +x, namely:

sx () {
    export PS4='+ [${BASH_SOURCE##*/}:${LINENO}]'
    set -x
}

and

sz () {
    set +x
    export PS4=
}

These 2 functions are in a file functons.sh which is sourced from ~/.bashrc, and visible online here.

Immediately after logging in to a new bash session I try to find out where the sz() function is like this:

$ shopt -s extdebug; declare -F sz; shopt -u extdebug
sz 25 /Users/jab/src/git/hub/jab/src/bash/keyboard/z.sh

This shows that bash thinks the sz() function is declared in z.sh, but at that line there is a different function, zzz(), online here.

The result for the sx() function (and all my myriad other functions) is correct

$ shopt -s extdebug; declare -F sx; shopt -u extdebug
sx 428 /Users/jab/src/git/hub/jab3/src/bash/functons.sh

Why does the declare -F comand get the wrong result for the sz function?

I have 2 small functions to abbreviate set -x / set +x, namely:

sx () {
    export PS4='+ [${BASH_SOURCE##*/}:${LINENO}]'
    set -x
}

and

sz () {
    set +x
    export PS4=
}

These 2 functions are in a file functons.sh which is sourced from ~/.bashrc, and visible online here.

Immediately after logging in to a new bash session I try to find out where the sz() function is like this:

$ shopt -s extdebug; declare -F sz; shopt -u extdebug
sz 25 /Users/jab/src/git/hub/jab/src/bash/keyboard/z.sh

This shows that bash thinks the sz() function is declared in z.sh, but at that line there is a different function, zzz(), online here.

The result for the sx() function (and all my other functions) is correct

$ shopt -s extdebug; declare -F sx; shopt -u extdebug
sx 428 /Users/jab/src/git/hub/jab3/src/bash/functons.sh

Why does the declare -F comand get the wrong result for the sz function? Do I need extra options (to the command itself or shopt)?

I have 2 small functions to abbreviate set -x / set +x, namely:

sx () {
    export PS4='+ [${BASH_SOURCE##*/}:${LINENO}]'
    set -x
}

and

sz () {
    set +x
    export PS4=
}

These 2 functions are in a file functons.sh which is sourced from ~/.bashrc, and visible online here.

Immediately after logging in to a new bash session I try to find out where the sz() function is like this:

$ shopt -s extdebug; declare -F sz; shopt -u extdebug
sz 25 /Users/jab/src/git/hub/jab/src/bash/keyboard/z.sh

This shows that bash thinks the sz() function is declared in z.sh, but at that line there is a different function, zzz(), online here.

The result for the sx() function (and all my myriad other functions) is correct

$ shopt -s extdebug; declare -F sx; shopt -u extdebug
sx 428 /Users/jab/src/git/hub/jab3/src/bash/functons.sh

Why does the declare -F comand get the wrong result for the sz function? Do I need extra options (to the command itself or shopt)?