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5
  • my guess is that $hostn is define in your first sshpass but the variable leave only during this execution, when you execute sshpass for the second time the variable $hostn doesn't exit anymore Commented Apr 24, 2018 at 9:31
  • A space in your password (or any globbing characters) may confuse your code as $oldpass in never properly quoted. Also, backslashes will not be read correctly as you're not using -r with read. In general, your script is a quoting minefield. Commented Apr 24, 2018 at 9:33
  • Depending on your version of Linux it may serve you better to use hostnamectl to set the host name. Commented Apr 24, 2018 at 9:40
  • Since you're trying to pass multiple commands on the same line (escaping the newlines), each command has to be terminated by ;. Otherwise you'll be trying to execute echo something read newhost sed ... etc. as a single command. Commented Apr 24, 2018 at 9:42
  • Thanks for your help i already put script working Its more simple and work Commented Apr 24, 2018 at 9:48