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Nov 30, 2017 at 18:19 comment added CoreyJJohnson Interesting. I'm having trouble wrapping my head around what you're saying but it fully makes sense. Thanks.
Nov 30, 2017 at 13:36 comment added Stéphane Chazelas No, the shell passes arguments to echo and echo writes the concatenation of them with space and a newline character to the pipe. $IFS is involved in the read builtin command and unquoted parameter and arithmetic expansions and command substitutions and the expansion of "$*" and "${array[*]}" and that's about it.
Nov 30, 2017 at 13:29 comment added CoreyJJohnson The shell sends the arguments to sed via the pipeline. I believe that $IFS still applies here.
Nov 27, 2017 at 19:44 comment added Stéphane Chazelas Note that the only command that is potentially affected by $IFS in there is echo $SHELL as you forgot to quote the variable expansion. Other than that, the value of $IFS is not relevant here.
Nov 27, 2017 at 18:30 history edited CoreyJJohnson CC BY-SA 3.0
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Nov 27, 2017 at 18:15 history answered CoreyJJohnson CC BY-SA 3.0